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Popular >

y^'+2y=12

Solution

y^{^{'}} + 2 y = 12

Solution

y = - e^{- 2 t - c_{1}} + 6

Solution steps

y^{'} (t) + 2 y = 12

Solve separable ODE:

y = - e^{- 2 t - c_{1}} + 6

y = - e^{- 2 t - c_{1}} + 6

Graph

Popular Examples

y^{^{'}} + 2 y = 11

(dx)/(dt)=3(x^2+1),x(pi/4)=1

\frac{d x}{d t} = 3 (x^{2} + 1), x (\frac{π}{4}) = 1

(1-x^2)^{1/2}y^'=(y^2-2y+1)arcsin(x)

(1 - x^{2})^{\frac{1}{2}} y^{^{'}} = (y^{2} - 2 y + 1) arcsin (x)

(dy)/(dx)=8sqrt(xy)

\frac{d y}{d x} = 8 x y

y^{^{'}} = y^{(\frac{1}{2})}

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=12 ?
The solution for y^'+2y=12 is y=-e^{-2t-c_{1}}+6