What is the solution for (x^2-14x+45)(dy)/(dx)=y ?

The solution for (x^2-14x+45)(dy)/(dx)=y is y=(c_{1}\sqrt[4]{x-9})/(\sqrt[4]{x-5)}

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(x^2-14x+45)(dy)/(dx)=y

(x^{2} - 14 x + 45) \frac{d y}{d x} = y

y = \frac{c _{1} 4 x - 9}{4 x - 5}

Solution steps

(x^{2} - 14 x + 45) \frac{d y}{d x} = y

Solve separable ODE:

y = \frac{c _{1} 4 x - 9}{4 x - 5}

y = \frac{c _{1} 4 x - 9}{4 x - 5}

\frac{d y}{d t} = \frac{[ 2 t ]}{[ y + y t ^{2} ]}

y^{^{'}} + 2 x y = 13 x

2 x (\frac{d y}{d x}) = y^{2}

\frac{d y}{d x} + \frac{x y}{1 - x ^{2}} = \frac{x y ^{2}}{1 - x ^{2}}

\frac{df}{d x} = - f (x)

What is the solution for (x^2-14x+45)(dy)/(dx)=y ?
The solution for (x^2-14x+45)(dy)/(dx)=y is y=(c_{1}\sqrt[4]{x-9})/(\sqrt[4]{x-5)}