What is the solution for (dx}{dy}=\frac{1+x^2)/y ?

The solution for (dx}{dy}=\frac{1+x^2)/y is x=tan(ln(y)+c_{1})

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(dx}{dy}=\frac{1+x^2)/y

\frac{d x}{d y} = \frac{1 + x ^{2}}{y}

x = tan (ln (y) + c_{1})

Solution steps

\frac{d x}{d y} = \frac{1 + x ^{2}}{y}

Solve separable ODE:

x = tan (ln (y) + c_{1})

x = tan (ln (y) + c_{1})

cos (y) \frac{d y}{d x} = \frac{- x sin ( y )}{1 + x ^{2}}

2 x^{^{'}} + x = 10

y y^{^{'}} = x e^{- y^{2}}

sin (3 x) d x + 2 y \cdot cos^{3} (3 x) d y = 0

\frac{d y}{d x} y x + 1 = 4

What is the solution for (dx}{dy}=\frac{1+x^2)/y ?
The solution for (dx}{dy}=\frac{1+x^2)/y is x=tan(ln(y)+c_{1})