What is the solution for e^{2x}(dy)/(dx)= 2/y ?

The solution for e^{2x}(dy)/(dx)= 2/y is y=sqrt(-2e^{-2x)+c_{1}},y=-sqrt(-2e^{-2x)+c_{1}}

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e^{2x}(dy)/(dx)= 2/y

e^{2 x} \frac{d y}{d x} = \frac{2}{y}

y = - 2 e^{- 2 x} + c_{1}, y = - - 2 e^{- 2 x} + c_{1}

Solution steps

e^{2 x} \frac{d y}{d x} = \frac{2}{y}

Solve separable ODE:

y = - 2 e^{- 2 x} + c_{1}, y = - - 2 e^{- 2 x} + c_{1}

y = - 2 e^{- 2 x} + c_{1}, y = - - 2 e^{- 2 x} + c_{1}

ln (x) y^{^{'}} - (\frac{2 \cdot y}{x}) = 0

\frac{d x}{d y} = sin (5 x)

\frac{d y}{d x} y = ln (ln (ln (x)))

\frac{d y}{d t} = 2 t cos^{2} (y), y (0) = \frac{π}{4}

(x + H (x) x) d x + x (H (x) d x + x d H (x)) = 0

What is the solution for e^{2x}(dy)/(dx)= 2/y ?
The solution for e^{2x}(dy)/(dx)= 2/y is y=sqrt(-2e^{-2x)+c_{1}},y=-sqrt(-2e^{-2x)+c_{1}}