What is the solution for y^'sqrt(1-x^2)+sqrt(1-y^2)=0 ?

The solution for y^'sqrt(1-x^2)+sqrt(1-y^2)=0 is y=sin(-arcsin(x)+c_{1})

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y^'sqrt(1-x^2)+sqrt(1-y^2)=0

y^{^{'}} 1 - x^{2} + 1 - y^{2} = 0

y = sin (- arcsin (x) + c_{1})

Solution steps

y^{'} (x) 1 - x^{2} + 1 - y^{2} = 0

Solve separable ODE:

y = sin (- arcsin (x) + c_{1})

y = sin (- arcsin (x) + c_{1})

\frac{1}{1 + y ^{2}} y^{^{'}} = x

y^{^{'}} + 2 y t = 0, y (1) = \frac{( e + 3 )}{2}

\frac{d y}{d x} = 14 e^{5 x - 4 y}

(4 x - 8) d x = (6 y - 10) d y

e^{x} 3 y y^{^{'}} = e^{- y} + e^{- 4 x - y}

What is the solution for y^'sqrt(1-x^2)+sqrt(1-y^2)=0 ?
The solution for y^'sqrt(1-x^2)+sqrt(1-y^2)=0 is y=sin(-arcsin(x)+c_{1})