What is the solution for a(xdy+2ydx)=xydx ?

The solution for a(xdy+2ydx)=xydx is y=(e^{(x+c_{1})/a})/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a(xdy+2ydx)=xydx

a (x d y + 2 y d x) = x y d x

y = \frac{e ^{\frac{x + c _{1}}{a}}}{x ^{2}}

Solution steps

a (x d y + 2 y d x) = x y d x

Solve separable ODE:

y = \frac{e ^{\frac{x + c _{1}}{a}}}{x ^{2}}

y = \frac{e ^{\frac{x + c _{1}}{a}}}{x ^{2}}

y^{^{'}} = y x

\frac{d y}{d x} y = 1

\frac{d v}{d t} + \frac{- k v ( t )}{0.018} = - 9.81

\frac{d y}{d t} = - 0.06 y

y^{5} \frac{d y}{d x} = 2 x^{4} y^{6} - 6 x^{4}

What is the solution for a(xdy+2ydx)=xydx ?
The solution for a(xdy+2ydx)=xydx is y=(e^{(x+c_{1})/a})/(x^2)