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Popular >

y-xy^'=1+x^2y^'

Solution

y - x y^{^{'}} = 1 + x^{2} y^{^{'}}

Solution

y = - \frac{c _{1} x}{x + 1} + 1

Solution steps

y - x y^{'} (x) = 1 + x^{2} y^{'} (x)

Solve separable ODE:

y = - \frac{c _{1} x}{x + 1} + 1

y = - \frac{c _{1} x}{x + 1} + 1

Graph

Popular Examples

(x^2+1)y^3+x^2*(dy)/(dx)=0

(x^{2} + 1) y^{3} + x^{2} \cdot \frac{d y}{d x} = 0

x(dy)/(dx)-yln(y)=0

x \frac{d y}{d x} - y ln (y) = 0

15.158y^'+y=0,y(0)=14.855

15.158 y^{^{'}} + y = 0, y (0) = 14.855

x \frac{d y}{d x} = - y

(dy)/(dx)=xy^2e^x

\frac{d y}{d x} = x y^{2} e^{x}

Frequently Asked Questions (FAQ)

What is the solution for y-xy^'=1+x^2y^' ?
The solution for y-xy^'=1+x^2y^' is y=-(c_{1}x)/(x+1)+1