What is the solution for (dx)/(dt)=14-0.84x ?

The solution for (dx)/(dt)=14-0.84x is x=-(e^{-0.84t-c_{1}})/(0.84)+(14)/(0.84)

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(dx)/(dt)=14-0.84x

\frac{d x}{d t} = 14 - 0.84 x

x = - \frac{e ^{- 0.84 t - c_{1}}}{0.84} + \frac{14}{0.84}

Solution steps

\frac{d x}{d t} = 14 - 0.84 x

Solve separable ODE:

x = - \frac{e ^{- 0.84 t - c_{1}}}{0.84} + \frac{14}{0.84}

x = - \frac{e ^{- 0.84 t - c_{1}}}{0.84} + \frac{14}{0.84}

2 x + 4 y \frac{d y}{d x} - c = 0

\frac{d y}{d x} = (y + 5) (2 x + 1)

\frac{d y}{d x} = 0.32 y

\frac{d y}{d x} = (1 + 2 \cdot x) \cdot y

1 + y^{2} d x + x y ln (x) d y = 0

What is the solution for (dx)/(dt)=14-0.84x ?
The solution for (dx)/(dt)=14-0.84x is x=-(e^{-0.84t-c_{1}})/(0.84)+(14)/(0.84)