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Popular >

2+y^'=6y,y(-2)=8

Solution

2 + y^{^{'}} = 6 y, y (- 2) = 8

Solution

y = \frac{23 e ^{6 t + 12}}{3} + \frac{1}{3}

Solution steps

2 + y^{'} (t) = 6 y

Solve separable ODE:

y = \frac{23 e ^{6 t + 12}}{3} + \frac{1}{3}

y = \frac{23 e ^{6 t + 12}}{3} + \frac{1}{3}

Graph

Popular Examples

y^'=-(46t)/y ,y(5)=2

y^{^{'}} = - \frac{46 t}{y}, y (5) = 2

y^'y=(4x^3+5)(4x^7-7)

y^{^{'}} y = (4 x^{3} + 5) (4 x^{7} - 7)

4(5x-3)^2(dy)/(dx)=2y-4

4 (5 x - 3)^{2} \frac{d y}{d x} = 2 y - 4

(dy}{dx}=\frac{2(5-y))/x

\frac{d y}{d x} = \frac{2 ( 5 - y )}{x}

xy^3dx-(y+1)e^{-x}dy=0

x y^{3} d x - (y + 1) e^{- x} d y = 0

Frequently Asked Questions (FAQ)

What is the solution for 2+y^'=6y,y(-2)=8 ?
The solution for 2+y^'=6y,y(-2)=8 is y=(23e^{6t+12})/3+1/3