What is the solution for y^'=(1-11x)y^2,y(0)=-1/9 ?

The solution for y^'=(1-11x)y^2,y(0)=-1/9 is y=-2/(2x-11x^2+18)

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y^'=(1-11x)y^2,y(0)=-1/9

y^{^{'}} = (1 - 11 x) y^{2}, y (0) = - \frac{1}{9}

y = - \frac{2}{2 x - 11 x ^{2} + 18}

Solution steps

y^{'} (x) = (1 - 11 x) y^{2}

Solve separable ODE:

y = - \frac{2}{2 x - 11 x ^{2} + 18}

y = - \frac{2}{2 x - 11 x ^{2} + 18}

x y (y + 2) d x - (y + 1) d y = 0

y^{^{'}} csc (t) = \frac{- y ^{17}}{16}

7 y y^{^{'}} = 3 x

y^{^{'}} = 6 x^{2} (1 - 7 e^{- y})

e^{x + y} sin (x) d x + (2 y + 1) e^{- y^{2}} d y = 0

What is the solution for y^'=(1-11x)y^2,y(0)=-1/9 ?
The solution for y^'=(1-11x)y^2,y(0)=-1/9 is y=-2/(2x-11x^2+18)