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Popular >

y^'=-y+7

Solution

y^{^{'}} = - y + 7

Solution

y = e^{- t - c_{1}} + 7

Solution steps

y^{'} (t) = - y + 7

Solve separable ODE:

y = e^{- t - c_{1}} + 7

y = e^{- t - c_{1}} + 7

Graph

Popular Examples

derivative of (x^2/(a^2)-(y^2)/(b^2))=1

\frac{d}{d x} (\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}}) = 1

2yt^3dy+3y^2t^2dt=0

2 y t^{3} d y + 3 y^{2} t^{2} d t = 0

y^{^{'}} = 4 x^{2} y

xln(x)(dy)/(dx)= 1/(y^2)

x ln (x) \frac{d y}{d x} = \frac{1}{y ^{2}}

y^'=((x-2)^2)/y ,y(3)=1

y^{^{'}} = \frac{( x - 2 ) ^{2}}{y}, y (3) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=-y+7 ?
The solution for y^'=-y+7 is y=e^{-t-c_{1}}+7