en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=xy-8x

Solution

y^{^{'}} = x y - 8 x

Solution

y = e^{\frac{x ^{2}}{2} + c_{1}} + 8

Solution steps

y^{'} (x) = x y - 8 x

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} + 8

y = e^{\frac{x ^{2}}{2} + c_{1}} + 8

Graph

Popular Examples

x^'=-(1-x)(2-x)

x^{^{'}} = - (1 - x) (2 - x)

(dP)/(dt)=sqrt(Pt),P(1)=5

\frac{d P}{d t} = Pt, P (1) = 5

(dy)/(dt)=10y-2y^2

\frac{d y}{d t} = 10 y - 2 y^{2}

y^{-1}dy+y*e^{cos(x)}*sin(x)dx=0

y^{- 1} d y + y \cdot e^{c o s (x)} \cdot sin (x) d x = 0

(dy)/(dx)=((2x+xy^2)/(4y+yx^2))

\frac{d y}{d x} = (\frac{2 x + x y ^{2}}{4 y + y x ^{2}})

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy-8x ?
The solution for y^'=xy-8x is y=e^{(x^2)/2+c_{1}}+8