What is the solution for (dh)/(dt)=-h^4 ?

The solution for (dh)/(dt)=-h^4 is h=-1/(\sqrt[3]{3(-t+c_{1))}}

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(dh)/(dt)=-h^4

\frac{d h}{d t} = - h^{4}

h = - \frac{1}{3 3 ( - t + c _{1} )}

Solution steps

\frac{d h}{d t} = - h^{4}

Solve separable ODE:

h = - \frac{1}{3 3 ( - t + c _{1} )}

h = - \frac{1}{3 3 ( - t + c _{1} )}

\frac{d y}{d x} = \frac{y cos ( x )}{7 + y ^{2}}, y (0) = 1

3 e^{t} tan (y) d t + (2 - e^{t}) sec^{2} (y) d y = 0

y^{^{'}} = 2 x^{3} y

y^{^{'}} y = t, y (3) = - 3

\frac{d x}{d y} = e^{2 x + 3 y}, x (0) = 1

What is the solution for (dh)/(dt)=-h^4 ?
The solution for (dh)/(dt)=-h^4 is h=-1/(\sqrt[3]{3(-t+c_{1))}}