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Popular >

y^'= y/(x+x^2)

Solution

y^{^{'}} = \frac{y}{x + x ^{2}}

Solution

y = \frac{c _{1} x}{x + 1}

Solution steps

y^{'} (x) = \frac{y}{x + x ^{2}}

Solve separable ODE:

y = \frac{c _{1} x}{x + 1}

y = \frac{c _{1} x}{x + 1}

Popular Examples

y^{^{'}} = e^{x} sec (y)

y^{7/2}(dy)/(dx)-y^3=-y^{9/2}

y^{\frac{7}{2}} \frac{d y}{d x} - y^{3} = - y^{\frac{9}{2}}

(dy)/(dx)xln(x)-y=0

\frac{d y}{d x} x ln (x) - y = 0

y^'=e^{7x-10y},y(0)=0

y^{^{'}} = e^{7 x - 10 y}, y (0) = 0

y^'csc(t)=(-y^{19})/(18)

y^{^{'}} csc (t) = \frac{- y ^{19}}{18}

Frequently Asked Questions (FAQ)

What is the solution for y^'= y/(x+x^2) ?
The solution for y^'= y/(x+x^2) is y=(c_{1}x)/(x+1)