What is (\partial)/(\partial z)(x^3yz^2) ?

The answer to (\partial)/(\partial z)(x^3yz^2) is 2x^3yz

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(\partial)/(\partial z)(x^3yz^2)

\frac{\partial}{\partial z} (x^{3} y z^{2})

2 x^{3} yz

Solution steps

\frac{\partial}{\partial z} (x^{3} y z^{2})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{3} y \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{3} y \cdot 2 z^{2 - 1}

Simplify

= 2 x^{3} yz

\frac{d}{d x} (0.6 e^{5 x})

\frac{d}{d x} (x e^{x} ln (x))

f (x) = 1 - y^{2}

x \to 0 + lim (\frac{3}{e ^{x} + 1})

\frac{d y}{d x} - tan (x) y = e^{11 x}

What is (\partial)/(\partial z)(x^3yz^2) ?
The answer to (\partial)/(\partial z)(x^3yz^2) is 2x^3yz