What is the solution for y+y^'arcsin(x)=0 ?

The solution for y+y^'arcsin(x)=0 is y=e^{-\Ci(arcsin(x))+c_{1}}

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y+y^'arcsin(x)=0

y + y^{^{'}} arcsin (x) = 0

y = e^{- Ci (a r c s i n (x)) + c_{1}}

Solution steps

y + y^{'} (x) arcsin (x) = 0

Solve separable ODE:

y = e^{- Ci (a r c s i n (x)) + c_{1}}

y = e^{- Ci (a r c s i n (x)) + c_{1}}

\frac{d y}{d x} = (x^{2} + 2) y^{\frac{1}{2}}

\frac{d y}{d x} = - \frac{y ( 1 - x )}{x ( 1 - y )}

y \frac{d y}{d x} - x^{2} = x^{2} y

\frac{d y}{d x} = \frac{2}{5 x y} x, y > 0

y^{^{'}} = \frac{x y}{x - 8}

What is the solution for y+y^'arcsin(x)=0 ?
The solution for y+y^'arcsin(x)=0 is y=e^{-\Ci(arcsin(x))+c_{1}}