What is the solution for (dy)/(dx)=(e^{7x+y})/(y-4) ?

The solution for (dy)/(dx)=(e^{7x+y})/(y-4) is y=-\W((1/7 e^{7x}+c_{1})e^3)+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(e^{7x+y})/(y-4)

\frac{d y}{d x} = \frac{e ^{7 x + y}}{y - 4}

y = - W ((\frac{1}{7} e^{7 x} + c_{1}) e^{3}) + 3

Solution steps

\frac{d y}{d x} = \frac{e ^{7 x + y}}{y - 4}

Solve separable ODE:

y = - W ((\frac{1}{7} e^{7 x} + c_{1}) e^{3}) + 3

y = - W ((\frac{1}{7} e^{7 x} + c_{1}) e^{3}) + 3

\frac{d P}{d t} = \frac{1}{20} (1 - \frac{P}{1000})

(x + 1) y y^{^{'}} = y^{2} + 1, y (1) = 3

x y^{^{'}} = e^{8 y + x}

y = 1 + y^{^{'}}

\frac{d P}{d t} = P (1 - \frac{P}{1800})

What is the solution for (dy)/(dx)=(e^{7x+y})/(y-4) ?
The solution for (dy)/(dx)=(e^{7x+y})/(y-4) is y=-\W((1/7 e^{7x}+c_{1})e^3)+3