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Popular >

sec(x)y^'+y=2

Solution

sec (x) y^{^{'}} + y = 2

Solution

y = - e^{- s i n (x) - c_{1}} + 2

Solution steps

sec (x) y^{'} (x) + y = 2

Solve separable ODE:

y = - e^{- s i n (x) - c_{1}} + 2

y = - e^{- s i n (x) - c_{1}} + 2

Popular Examples

(dy)/(dx)=(1-y)*cos(x)

\frac{d y}{d x} = (1 - y) \cdot cos (x)

(2x+3)y^'=xy(2x+3)^{1/2}

(2 x + 3) y^{^{'}} = x y (2 x + 3)^{\frac{1}{2}}

sqrt(1+y^2)-xy^'=0

1 + y^{2} - x y^{^{'}} = 0

e 1/x (dy)/(dx)+4y=2

e \frac{1}{x} \frac{d y}{d x} + 4 y = 2

y^'=(3x)/y sqrt(1+y^2)

y^{^{'}} = \frac{3 x}{y} 1 + y^{2}

Frequently Asked Questions (FAQ)

What is the solution for sec(x)y^'+y=2 ?
The solution for sec(x)y^'+y=2 is y=-e^{-sin(x)-c_{1}}+2