What is the solution for y^'=y(a/(x^2)+bx) ?

The solution for y^'=y(a/(x^2)+bx) is y=e^{-a/x+(bx^2)/2+c_{1}}

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y^'=y(a/(x^2)+bx)

y^{^{'}} = y (\frac{a}{x ^{2}} + b x)

y = e^{- \frac{a}{x} + \frac{b x ^{2}}{2} + c_{1}}

Solution steps

y^{'} (x) = y (\frac{a}{x ^{2}} + b x)

Solve separable ODE:

y = e^{- \frac{a}{x} + \frac{b x ^{2}}{2} + c_{1}}

y = e^{- \frac{a}{x} + \frac{b x ^{2}}{2} + c_{1}}

\frac{d y}{d t} = 0.48 - \frac{y}{240}

f (x) = f^{^{'}} (x) (4 x + 9)^{5}

\frac{d y}{d x} = - 7 (- 4 - y)

\frac{d h}{d t} = - \frac{1}{72} h

(y) sin (x) + y^{^{'}} = sin (x)

What is the solution for y^'=y(a/(x^2)+bx) ?
The solution for y^'=y(a/(x^2)+bx) is y=e^{-a/x+(bx^2)/2+c_{1}}