What is the solution for sin(x)dx+1/y dy=0,y(0)=0 ?

The solution for sin(x)dx+1/y dy=0,y(0)=0 is y=e^{cos(x)+c_{1}}

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sin(x)dx+1/y dy=0,y(0)=0

sin (x) d x + \frac{1}{y} d y = 0, y (0) = 0

y = e^{c o s (x) + c_{1}}

Solution steps

sin (x) d x + \frac{1}{y} d y = 0

Solve separable ODE:

y = e^{c o s (x) + c_{1}}

y = e^{c o s (x) + c_{1}}

\frac{d y}{d x} = x^{8} y^{- 5}, y (0) = 2

x^{2} \frac{d x}{d y} = e^{2}

\frac{d y}{d x} = a (500 - y)

\frac{f ^{^{'}} ( x )}{f ( x )} = \frac{2}{x}

\frac{d y}{d x} = \frac{y cos ( x )}{3 x}

What is the solution for sin(x)dx+1/y dy=0,y(0)=0 ?
The solution for sin(x)dx+1/y dy=0,y(0)=0 is y=e^{cos(x)+c_{1}}