What is the solution for 2y(dy)/(dx)=xe^x ?

The solution for 2y(dy)/(dx)=xe^x is y=sqrt(e^xx-e^x+c_{1)},y=-sqrt(e^xx-e^x+c_{1)}

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2y(dy)/(dx)=xe^x

2 y \frac{d y}{d x} = x e^{x}

y = e^{x} x - e^{x} + c_{1}, y = - e^{x} x - e^{x} + c_{1}

Solution steps

2 y \frac{d y}{d x} = x e^{x}

Solve separable ODE:

y = e^{x} x - e^{x} + c_{1}, y = - e^{x} x - e^{x} + c_{1}

y = e^{x} x - e^{x} + c_{1}, y = - e^{x} x - e^{x} + c_{1}

\frac{d y}{d x} y = arccsc (5 x^{2} + 1)

\frac{d y}{d x} = \frac{10 x}{y}

\frac{d y}{d x} = 2 e^{x - y}, y (0) = ln (8)

(x^{2} + 1) (y^{2} - 1) + x y y^{^{'}} = 0

2 y^{^{'}} = y + 1

What is the solution for 2y(dy)/(dx)=xe^x ?
The solution for 2y(dy)/(dx)=xe^x is y=sqrt(e^xx-e^x+c_{1)},y=-sqrt(e^xx-e^x+c_{1)}