What is the derivative of (k^2+x^2^k) ?

The derivative of (k^2+x^2^k) is k(k^2+x^2)^{k-1}*2x

What is the first derivative of (k^2+x^2^k) ?

The first derivative of (k^2+x^2^k) is k(k^2+x^2)^{k-1}*2x

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\frac{d}{d x} ((k^{2} + x^{2})^{k})

k (k^{2} + x^{2})^{k - 1} \cdot 2 x

Solution steps

\frac{d}{d x} ((k^{2} + x^{2})^{k})

Apply the chain rule:

k (k^{2} + x^{2})^{k - 1} \frac{d}{d x} (k^{2} + x^{2})

= k (k^{2} + x^{2})^{k - 1} \frac{d}{d x} (k^{2} + x^{2})

\frac{d}{d x} (k^{2} + x^{2}) = 2 x

= k (k^{2} + x^{2})^{k - 1} \cdot 2 x

n = 1 \sum \infty \frac{3}{n ^{6}}

\frac{d}{d x} (\frac{( x - 3 )}{x - 3})

x \to 0 lim (\frac{x ^{2} - 1}{x ^{2}})

\frac{3 x - 8}{x}

\frac{d}{d x} (\frac{e ^{x} + e ^{- x}}{2})

What is the derivative of (k^2+x^2^k) ?
The derivative of (k^2+x^2^k) is k(k^2+x^2)^{k-1}*2x
What is the first derivative of (k^2+x^2^k) ?
The first derivative of (k^2+x^2^k) is k(k^2+x^2)^{k-1}*2x