What is the solution for y^'=0.6y(1-y/(1120)) ?

The solution for y^'=0.6y(1-y/(1120)) is y=-(1120e^{0.6t+c_{1}})/(1-e^{0.6t+c_{1)}}

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y^'=0.6y(1-y/(1120))

y^{^{'}} = 0.6 y (1 - \frac{y}{1120})

y = - \frac{1120 e ^{0.6 t + c_{1}}}{1 - e ^{0.6 t + c_{1}}}

Solution steps

y^{'} (t) = 0.6 y (1 - \frac{y}{1120})

Solve separable ODE:

y = - \frac{1120 e ^{0.6 t + c_{1}}}{1 - e ^{0.6 t + c_{1}}}

y = - \frac{1120 e ^{0.6 t + c_{1}}}{1 - e ^{0.6 t + c_{1}}}

f (x) x + x f^{^{'}} (x) x + x^{2} f (x) x = 0

\frac{d y}{d x} = 20 x y

\frac{d y}{d x} + y = \frac{( 1 + y ^{2} )}{2 y}

\frac{d y}{d x} = \frac{( x - 8 )}{64 y - 384}

x y^{^{'}} + y ln (y) = 0

What is the solution for y^'=0.6y(1-y/(1120)) ?
The solution for y^'=0.6y(1-y/(1120)) is y=-(1120e^{0.6t+c_{1}})/(1-e^{0.6t+c_{1)}}