What is the solution for (dx)/(dy)y=x^2+2x ?

The solution for (dx)/(dy)y=x^2+2x is x=(2e^{2c_{1}}y^2)/(1-e^{2c_{1)}y^2}

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(dx)/(dy)y=x^2+2x

\frac{d x}{d y} y = x^{2} + 2 x

x = \frac{2 e ^{2 c_{1}} y ^{2}}{1 - e ^{2 c_{1}} y ^{2}}

Solution steps

\frac{d x}{d y} y = x^{2} + 2 x

Solve separable ODE:

x = \frac{2 e ^{2 c_{1}} y ^{2}}{1 - e ^{2 c_{1}} y ^{2}}

x = \frac{2 e ^{2 c_{1}} y ^{2}}{1 - e ^{2 c_{1}} y ^{2}}

\frac{d x}{d t} + \frac{t + 1}{2 t} x = \frac{t + 1}{x t}

h^{^{'}} = - 0.02215 \cdot h^{\frac{1}{2}}

y^{^{'}} = \frac{( x ^{3} x ^{4} - 1 )}{y ^{3}}

y^{^{'}} + 7 \frac{y}{x} = 0

\frac{d x}{d y} = \frac{x y ^{2} + x}{10 y ^{2}}

What is the solution for (dx)/(dy)y=x^2+2x ?
The solution for (dx)/(dy)y=x^2+2x is x=(2e^{2c_{1}}y^2)/(1-e^{2c_{1)}y^2}