What is the solution for (dy)/(dx)=xy^2,y(-3)=-1/5 ?

The solution for (dy)/(dx)=xy^2,y(-3)=-1/5 is y=-2/(x^2+1)

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(dy)/(dx)=xy^2,y(-3)=-1/5

\frac{d y}{d x} = x y^{2}, y (- 3) = - \frac{1}{5}

y = - \frac{2}{x ^{2} + 1}

Solution steps

\frac{d y}{d x} = x y^{2}

Solve separable ODE:

y = - \frac{2}{x ^{2} + 1}

y = - \frac{2}{x ^{2} + 1}

(- 4 x y^{2} - 4 y) d x + (- 4 x^{2} y - 4 x) d y = 0

\frac{d V}{d t} = 1 - 0.4 \cdot V

y^{^{'}} = \frac{3 t ^{2} y}{y + 1}

\frac{d y}{d x} y^{2} - x^{3} = 28

\frac{d}{d x} (x y^{4}) = 5

What is the solution for (dy)/(dx)=xy^2,y(-3)=-1/5 ?
The solution for (dy)/(dx)=xy^2,y(-3)=-1/5 is y=-2/(x^2+1)