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Popular >

y^'=((y+4))/x

Solution

y^{^{'}} = \frac{( y + 4 )}{x}

Solution

y = c_{1} x - 4

Solution steps

y^{'} (x) = \frac{( y + 4 )}{x}

Solve separable ODE:

y = c_{1} x - 4

y = c_{1} x - 4

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=((y+4))/x ?
The solution for y^'=((y+4))/x is y=c_{1}x-4