What is the solution for (y/(x+6x))+(ln(x)-2)y^'=0 ?

The solution for (y/(x+6x))+(ln(x)-2)y^'=0 is y=(c_{1})/(\sqrt[7]{ln(x)-2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y/(x+6x))+(ln(x)-2)y^'=0

(\frac{y}{x + 6 x}) + (ln (x) - 2) y^{^{'}} = 0

y = \frac{c _{1}}{7 ln ( x ) - 2}

Solution steps

(\frac{y}{x + 6 x}) + (ln (x) - 2) y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{7 ln ( x ) - 2}

y = \frac{c _{1}}{7 ln ( x ) - 2}

y^{^{'}} = 70 y x^{13}, y (1) = 2

\frac{d y}{d x} = e^{3 x - 5 y}

\frac{d y}{d x} = \frac{( 1 + 4 y ^{2} )}{e ^{x}}

\frac{d y}{d x} = - 8 x y^{2}, y (0) = 1

y^{^{'}} = \frac{2 x}{1 + 2 y}, y (2) = - 0.2

What is the solution for (y/(x+6x))+(ln(x)-2)y^'=0 ?
The solution for (y/(x+6x))+(ln(x)-2)y^'=0 is y=(c_{1})/(\sqrt[7]{ln(x)-2)}