What is the solution for (dy)/(dx)=-8/2 x^3y^8 ?

The solution for (dy)/(dx)=-8/2 x^3y^8 is y=-1/(\sqrt[7]{7(-x^4+c_{1))}}

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(dy)/(dx)=-8/2 x^3y^8

\frac{d y}{d x} = - \frac{8}{2} x^{3} y^{8}

y = - \frac{1}{7 7 ( - x ^{4} + c _{1} )}

Solution steps

\frac{d y}{d x} = - \frac{8}{2} x^{3} y^{8}

Solve separable ODE:

y = - \frac{1}{7 7 ( - x ^{4} + c _{1} )}

y = - \frac{1}{7 7 ( - x ^{4} + c _{1} )}

\frac{d P}{d t} = \frac{P}{2} - 100 P e^{- 2 t}

\frac{d y}{d x} = \frac{16 x}{e ^{y}}

y + y^{^{'}} - 72 y = 0

\frac{d y}{d x} = \frac{x 4 - y ^{2}}{1 - x ^{2}}

u^{^{'}} = 2 e^{5 x - H (x)}

What is the solution for (dy)/(dx)=-8/2 x^3y^8 ?
The solution for (dy)/(dx)=-8/2 x^3y^8 is y=-1/(\sqrt[7]{7(-x^4+c_{1))}}