What is the solution for x^'+(x-25)+(x-25)/3 =200 ?

The solution for x^'+(x-25)+(x-25)/3 =200 is x=(e^{(-4t-c_{1})/3})/(4)+175

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x^'+(x-25)+(x-25)/3 =200

x^{^{'}} + (x - 25) + \frac{x - 25}{3} = 200

x = \frac{e ^{\frac{- 4 t - c _{1}}{3}}}{4} + 175

Solution steps

x^{'} (t) + (x - 25) + \frac{x - 25}{3} = 200

Solve separable ODE:

x = \frac{e ^{\frac{- 4 t - c _{1}}{3}}}{4} + 175

x = \frac{e ^{\frac{- 4 t - c _{1}}{3}}}{4} + 175

y^{^{'}} - 10 y + 25 y = 0

\frac{d y}{d x} = \frac{y}{x ( 1 - x ^{2} )}

y^{^{'}} = 5 e^{x - y}, y (0) = ln (7)

y^{^{'}} + (8 x - 1) y = 0

\frac{d h}{d t} = (- \frac{3}{100} h - 19)

What is the solution for x^'+(x-25)+(x-25)/3 =200 ?
The solution for x^'+(x-25)+(x-25)/3 =200 is x=(e^{(-4t-c_{1})/3})/(4)+175