What is the solution for derivative of hg(x)=hg(x) ?

The solution for derivative of hg(x)=hg(x) is h(x)=(e^{x+c_{1}})/x

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derivative of hg(x)=hg(x)

\frac{d}{d x} (h g (x)) = h g (x)

h (x) = \frac{e ^{x + c_{1}}}{x}

Solution steps

\frac{d}{d x} (h (x) g (x)) = h (x) g (x)

Solve separable ODE:

h (x) = \frac{e ^{x + c_{1}}}{x}

h (x) = \frac{e ^{x + c_{1}}}{x}

y^{^{'}} + \frac{1}{a ^{2}} y = 0

\frac{d y}{d x} = (3 x - 2)^{3} e^{2 y}

2 x d x + sin (y) d y = 0, y (1) = 0

q^{^{'}} (p) = \frac{5400 p ^{2} q ( p )}{( p ^{3} + 2 ) ^{2}}

\frac{d y}{d x} = 4 x^{3} + x^{3} y^{2}

What is the solution for derivative of hg(x)=hg(x) ?
The solution for derivative of hg(x)=hg(x) is h(x)=(e^{x+c_{1}})/x