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Popular >

y^'=7e^{3x-5y}

Solution

y^{^{'}} = 7 e^{3 x - 5 y}

Solution

y = \frac{ln ( \frac{35}{3} e ^{3 x} + c _{1} )}{5}

Solution steps

y^{'} (x) = 7 e^{3 x - 5 y}

Solve separable ODE:

y = \frac{ln ( \frac{35}{3} e ^{3 x} + c _{1} )}{5}

y = \frac{ln ( \frac{35}{3} e ^{3 x} + c _{1} )}{5}

Popular Examples

(dV)/(dt)=(10-4/100 V),V(0)=0

\frac{d V}{d t} = (10 - \frac{4}{100} V), V (0) = 0

\frac{d v}{df} = v \cdot f

ye^x(dy)/(dx)=e^{-y}+e^{-3x-y}

y e^{x} \frac{d y}{d x} = e^{- y} + e^{- 3 x - y}

y=((x+1)^3)/(x^{3/2)}(dy)/(dx)

y = \frac{( x + 1 ) ^{3}}{x ^{\frac{3}{2}}} \frac{d y}{d x}

y^{^{'}} = y^{3} e^{- x}

Frequently Asked Questions (FAQ)

What is the solution for y^'=7e^{3x-5y} ?
The solution for y^'=7e^{3x-5y} is y=(ln(35/3 e^{3x}+c_{1}))/5