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Popular >

y^'=xy-x-2y+2

Solution

y^{^{'}} = x \cdot y - x - 2 \cdot y + 2

Solution

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} + 1

Solution steps

y^{'} (x) = x \cdot y - x - 2 \cdot y + 2

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} + 1

y = e^{\frac{x ^{2}}{2} - 2 x + c_{1}} + 1

Popular Examples

(1+x^4)dy+x(1+4y^2)dx=0,y(1)=1

(1 + x^{4}) d y + x (1 + 4 y^{2}) d x = 0, y (1) = 1

(dx)/(dt)=12*x*t

\frac{d x}{d t} = 12 \cdot x \cdot t

(dy)/(dx)=12yx^2

\frac{d y}{d x} = 12 y x^{2}

y=x^3*e^{-2x}cos(3x)(dy)/(dx)

y = x^{3} \cdot e^{- 2 x} cos (3 x) \frac{d y}{d x}

(3y)dx+(2x)dy=0

(3 y) d x + (2 x) d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=x*y-x-2*y+2 ?
The solution for y^'=x*y-x-2*y+2 is y=e^{(x^2)/2-2x+c_{1}}+1