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Popular >

2yy^'=9t^2,y(0)=2

Solution

2 y y^{^{'}} = 9 t^{2}, y (0) = 2

Solution

y = 3 t^{3} + 4

Solution steps

2 y y^{'} (t) = 9 t^{2}

Solve separable ODE:

y = 3 t^{3} + 4

y = 3 t^{3} + 4

Popular Examples

x^{^{'}} = a + b \cdot x

sin(x)y^'+(sin^2(x))/(cos(x))y=0

sin (x) y^{^{'}} + \frac{sin ^{2} ( x )}{cos ( x )} y = 0

y^'=-1/5 y^2,y(0)=0.25

y^{^{'}} = - \frac{1}{5} y^{2}, y (0) = 0.25

4(dy)/(dx)=(e^ysin^2(x))/(ysec(x))

4 \frac{d y}{d x} = \frac{e ^{y} sin ^{2} ( x )}{y sec ( x )}

(dy)/(dx)+x*y=x*y^2

\frac{d y}{d x} + x \cdot y = x \cdot y^{2}

Frequently Asked Questions (FAQ)

What is the solution for 2yy^'=9t^2,y(0)=2 ?
The solution for 2yy^'=9t^2,y(0)=2 is y=sqrt(3t^3+4)