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Popular >

x^2y^'-y^2=0

Solution

x^{2} y^{^{'}} - y^{2} = 0

Solution

y = - \frac{x}{- 1 + c _{1} x}

Solution steps

x^{2} y^{'} (x) - y^{2} = 0

Solve separable ODE:

y = - \frac{x}{- 1 + c _{1} x}

y = - \frac{x}{- 1 + c _{1} x}

Popular Examples

(dx)/(dt)=r(1-x/k)

\frac{d x}{d t} = r (1 - \frac{x}{k})

y*(dy)/(dx)+2x-1=0

y \cdot \frac{d y}{d x} + 2 x - 1 = 0

2(dy)/(dx)=-4y+5

2 \frac{d y}{d x} = - 4 y + 5

(dy)/(dx)=xsqrt(y),x(1)=4

\frac{d y}{d x} = x y, x (1) = 4

(x+1)(t^2+1)=t(dx)/(dt)

(x + 1) (t^{2} + 1) = t \frac{d x}{d t}

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'-y^2=0 ?
The solution for x^2y^'-y^2=0 is y=-x/(-1+c_{1)x}