What is the tangent of 110x-16x^2 ?

The tangent of 110x-16x^2 is y=(110-32a_{0})x+16a_{0}^2

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tangent of 110x-16x^2

tangent of

110 x - 16 x^{2}

y = (110 - 32 a_{0}) x + 16 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 110 a_{0} - 16 a_{0}^{2})

Find the slope of

y = 110 x - 16 x^{2} : \frac{d y}{d x} = 110 - 32 x

Compute the slope of

y = 110 x - 16 x^{2}

x = a_{0} : m = 110 - 32 a_{0}

Find the line with slope m=

110 - 32 a_{0}

and passing through

(a_{0}, 110 a_{0} - 16 a_{0}^{2}) : y = (110 - 32 a_{0}) x + 16 a_{0}^{2}

y = (110 - 32 a_{0}) x + 16 a_{0}^{2}

\frac{d}{d x} (16)

\int \frac{7 - 6 x ^{3} + 4 x ^{6}}{x ^{6}} d x

\frac{d}{d x} (arctan (\frac{1}{3 x}))

n = 0 \sum \infty 3 (\frac{1}{2})^{n}

\frac{d}{d r} (\frac{r}{r ^{2} + 5})

What is the tangent of 110x-16x^2 ?
The tangent of 110x-16x^2 is y=(110-32a_{0})x+16a_{0}^2