en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+y/(200)=5

Solution

y^{^{'}} + \frac{y}{200} = 5

Solution

y = - e^{\frac{- t - c _{1}}{200}} + 1000

Solution steps

y^{'} (t) + \frac{y}{200} = 5

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{200}} + 1000

y = - e^{\frac{- t - c _{1}}{200}} + 1000

Popular Examples

(dy)/(dx)=14y+1,y=-1/14+12e^{14x}

\frac{d y}{d x} = 14 y + 1, y = - \frac{1}{14} + 12 e^{14 x}

(9x^2+2x)dx+(12y^3-4y)dy=0

(9 x^{2} + 2 x) d x + (12 y^{3} - 4 y) d y = 0

(dy)/(dx)=2x^5sqrt(y)

\frac{d y}{d x} = 2 x^{5} y

(dN)/(dt)+N=N*te^{t+2}

\frac{d N}{d t} + N = N \cdot t e^{t + 2}

(dy)/(dx)=((yx+5x))/(x^2+1)

\frac{d y}{d x} = \frac{( y x + 5 x )}{x ^{2} + 1}

Frequently Asked Questions (FAQ)

What is the solution for y^'+y/(200)=5 ?
The solution for y^'+y/(200)=5 is y=-e^{(-t-c_{1})/(200)}+1000