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Popular >

2zuduudu+u^2dz=0

Solution

2 z u d uu d u + u^{2} d z = 0

Solution

z (u) = e^{- 2 u + c_{1}}

Solution steps

2 z (u) u d uu d u + u^{2} d z (u) = 0

Solve separable ODE:

z (u) = e^{- 2 u + c_{1}}

z (u) = e^{- 2 u + c_{1}}

Popular Examples

(dy)/(dx)=(y-1)^2e^{x-7},y(7)=2

\frac{d y}{d x} = (y - 1)^{2} e^{x - 7}, y (7) = 2

(dx)/(dt)= 1/(xe^{t+9x)}

\frac{d x}{d t} = \frac{1}{x e ^{t + 9 x}}

(dy)/(dx)=(x^5y)/(sqrt(16-x^6))

\frac{d y}{d x} = \frac{x ^{5} y}{16 - x ^{6}}

y^'=0.0175*7-y/(2000)*7

y^{^{'}} = 0.0175 \cdot 7 - \frac{y}{2000} \cdot 7

y^'=(2y^4-2)/((4xy^3))

y^{^{'}} = \frac{2 y ^{4} - 2}{( 4 x y ^{3} )}

Frequently Asked Questions (FAQ)

What is the solution for 2zuduudu+u^2dz=0 ?
The solution for 2zuduudu+u^2dz=0 is z(u)=e^{-2u+c_{1}}