What is (\partial)/(\partial y)(x^2+y) ?

The answer to (\partial)/(\partial y)(x^2+y) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(x^2+y)

\frac{\partial}{\partial y} (x^{2} + y)

1

Solution steps

\frac{\partial}{\partial y} (x^{2} + y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 + 1

Simplify

= 1

f (x) = \frac{3 x + 1}{x ^{2} + 1}, (1, 2)

t \to 3 lim (\frac{2 t - 3}{t - 3})

y = 5 sec (x) - 10 cos (x), (\frac{π}{3}, 5)

\int (x - 3) x + 3 d x

f (x) = 4 - x

What is (\partial)/(\partial y)(x^2+y) ?
The answer to (\partial)/(\partial y)(x^2+y) is 1