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Popular >

y^'=x^2y+x^2

Solution

y^{^{'}} = x^{2} y + x^{2}

Solution

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

Solution steps

y^{'} (x) = x^{2} y + x^{2}

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

Graph

Popular Examples

y^'=y-y^3,y(0)=2

y^{^{'}} = y - y^{3}, y (0) = 2

(dy)/(dx)=x-2xy

\frac{d y}{d x} = x - 2 x y

((1/y)-(x/y))dx+(x^2*cos(y))dy=0,y(1)=pi

((\frac{1}{y}) - (\frac{x}{y})) d x + (x^{2} \cdot cos (y)) d y = 0, y (1) = π

derivative of ln(y)=ln((x^2-9)^{1/3})

\frac{d}{d x} (ln (y)) = ln ((x^{2} - 9)^{\frac{1}{3}})

- x y^{^{'}} + y = y^{- 1}

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2y+x^2 ?
The solution for y^'=x^2y+x^2 is y=e^{(x^3)/3+c_{1}}-1