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Popular >

(x^2-9)/x y^'+y=0

Solution

\frac{x ^{2} - 9}{x} y^{^{'}} + y = 0

Solution

y = \frac{c _{1}}{x ^{2} - 9}

Solution steps

\frac{x ^{2} - 9}{x} y^{'} (x) + y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 9}

y = \frac{c _{1}}{x ^{2} - 9}

Graph

Popular Examples

(dy)/(dx)=1+1/5 y

\frac{d y}{d x} = 1 + \frac{1}{5} y

((x^2-9))/x*(dy)/(dx)+y=0,y(5)=1

\frac{( x ^{2} - 9 )}{x} \cdot \frac{d y}{d x} + y = 0, y (5) = 1

x y y^{^{'}} = x + y y^{^{'}}

(dy)/(dx)=((3x^2)/(2y))

\frac{d y}{d x} = (\frac{3 x ^{2}}{2 y})

sqrt(1-x^2)y^'=xsqrt(4-y^2)

1 - x^{2} y^{^{'}} = x 4 - y^{2}

Frequently Asked Questions (FAQ)

What is the solution for (x^2-9)/x y^'+y=0 ?
The solution for (x^2-9)/x y^'+y=0 is y=(c_{1})/(sqrt(x^2-9))