What is the solution for (dy)/(dx)=((3x^2)/(e^y+1)) ?

The solution for (dy)/(dx)=((3x^2)/(e^y+1)) is y=-\W(1/(e^{-c_{1)-x^3}})+x^3+c_{1}

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(dy)/(dx)=((3x^2)/(e^y+1))

\frac{d y}{d x} = (\frac{3 x ^{2}}{e ^{y} + 1})

y = - W (\frac{1}{e ^{- c_{1} - x^{3}}}) + x^{3} + c_{1}

Solution steps

\frac{d y}{d x} = (\frac{3 x ^{2}}{e ^{y} + 1})

Solve separable ODE:

y = - W (\frac{1}{e ^{- c_{1} - x^{3}}}) + x^{3} + c_{1}

y = - W (\frac{1}{e ^{- c_{1} - x^{3}}}) + x^{3} + c_{1}

\frac{d y}{d x} = \frac{( y + 1 )}{2 x}

3 y^{2} (x - 3)^{2} \frac{d y}{d x} 3 y^{2} (x - 3)^{2} = k

\frac{d y}{d x} = e^{4 y + 6 x}

\frac{d y}{d x} = (y - 2)^{2}

(3 + x^{8}) \frac{d y}{d x} = \frac{x ^{7}}{y}

What is the solution for (dy)/(dx)=((3x^2)/(e^y+1)) ?
The solution for (dy)/(dx)=((3x^2)/(e^y+1)) is y=-\W(1/(e^{-c_{1)-x^3}})+x^3+c_{1}