What is the solution for (2dq)/(dt)+6q=2 ?

The solution for (2dq)/(dt)+6q=2 is q(t)=-(e^{-3t-c_{1}})/3+1/3

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(2dq)/(dt)+6q=2

\frac{2 d q}{d t} + 6 q = 2

q (t) = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{1}{3}

Solution steps

\frac{2 d q ( t )}{d t} + 6 q (t) = 2

Solve separable ODE:

q (t) = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{1}{3}

q (t) = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{1}{3}

\frac{d y}{d x} y = - 4 x ln (5 x + 2)

y^{2} \frac{d y}{d x} = x

\frac{d y}{d x} y = (2 x + 1)^{3}

\frac{d}{d x} (y^{2}) = x + 1

\frac{d y}{d x} = - \frac{y}{1200 + 10 x}

What is the solution for (2dq)/(dt)+6q=2 ?
The solution for (2dq)/(dt)+6q=2 is q(t)=-(e^{-3t-c_{1}})/3+1/3