What is the solution for y^'=3xsqrt(2y) ?

The solution for y^'=3xsqrt(2y) is y=(9x^4)/8+(3c_{1}x^2}{2sqrt(2)}+\frac{c_{1}^2)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=3xsqrt(2y)

y^{^{'}} = 3 x 2 y

y = \frac{9 x ^{4}}{8} + \frac{3 c _{1} x ^{2}}{2 2} + \frac{c _{1}^{2}}{4}

Solution steps

y^{'} (x) = 3 x 2 y

Solve separable ODE:

y = \frac{9 x ^{4}}{8} + \frac{3 c _{1} x ^{2}}{2 2} + \frac{c _{1}^{2}}{4}

y = \frac{9 x ^{4}}{8} + \frac{3 c _{1} x ^{2}}{2 2} + \frac{c _{1}^{2}}{4}

\frac{d}{d x} (f (x)^{- 1}) f (x) = \frac{1}{5} x + 5, x = 6

x \frac{d y}{d x} = x^{2} y^{2}

\frac{d y}{d x} = y^{2} \cdot x^{3}

y^{\frac{5}{2}} \frac{d y}{d x} - y^{2} = - y^{\frac{7}{2}}

P^{^{'}} = k P (t)

What is the solution for y^'=3xsqrt(2y) ?
The solution for y^'=3xsqrt(2y) is y=(9x^4)/8+(3c_{1}x^2}{2sqrt(2)}+\frac{c_{1}^2)/4