What is the solution for (dy)/(dx)+2y=1,y(0)= 5/2 ?

The solution for (dy)/(dx)+2y=1,y(0)= 5/2 is y= 1/2+2/(e^{2x)}

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(dy)/(dx)+2y=1,y(0)= 5/2

\frac{d y}{d x} + 2 y = 1, y (0) = \frac{5}{2}

y = \frac{1}{2} + \frac{2}{e ^{2 x}}

Solution steps

\frac{d y}{d x} + 2 y = 1

Solve linear ODE:

y = \frac{1}{2} + \frac{2}{e ^{2 x}}

y = \frac{1}{2} + \frac{2}{e ^{2 x}}

\int \frac{x - 1}{x ^{3} - 2 x ^{2}} d x

y = arcsin (3 5 x)

x \to 1 lim (2 3 x^{2} + 1)

y = \frac{1}{8 x ^{2}}, y = x, y = \frac{x}{6}

\frac{\partial}{\partial z} (2 x y z^{- 1})

What is the solution for (dy)/(dx)+2y=1,y(0)= 5/2 ?
The solution for (dy)/(dx)+2y=1,y(0)= 5/2 is y= 1/2+2/(e^{2x)}