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Popular >

y^'+2y=4xy

Solution

y^{^{'}} + 2 y = 4 x y

Solution

y = e^{2 (x^{2} - x) + c_{1}}

Solution steps

y^{'} (x) + 2 y = 4 x y

Solve separable ODE:

y = e^{2 (x^{2} - x) + c_{1}}

y = e^{2 (x^{2} - x) + c_{1}}

Popular Examples

(dx}{dy}=\frac{(x+2)^2)/x

\frac{d x}{d y} = \frac{( x + 2 ) ^{2}}{x}

(1+x^2)(dy)/(dx)-xy=0,y(2)=5

(1 + x^{2}) \frac{d y}{d x} - x y = 0, y (2) = 5

(dy)/(dx)=2sqrt((1-x^2)(1-y^2))

\frac{d y}{d x} = 2 (1 - x^{2}) (1 - y^{2})

3(dy)/(dx)=(4x)/(y^2)

3 \frac{d y}{d x} = \frac{4 x}{y ^{2}}

y^'=4x+xy,y(0)=-2

y^{^{'}} = 4 x + x y, y (0) = - 2

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=4xy ?
The solution for y^'+2y=4xy is y=e^{2(x^2-x)+c_{1}}