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Popular >

y^'=(2-y)/x

Solution

y^{^{'}} = \frac{2 - y}{x}

Solution

y = - \frac{c _{1}}{x} + 2

Solution steps

y^{'} (x) = \frac{2 - y}{x}

Solve separable ODE:

y = - \frac{c _{1}}{x} + 2

y = - \frac{c _{1}}{x} + 2

Popular Examples

(dy)/(dx)=-y,y(1)=3

\frac{d y}{d x} = - y, y (1) = 3

y^'=e^{4y+4x},y(0)=9

y^{^{'}} = e^{4 y + 4 x}, y (0) = 9

y^'=(x^2+3x)/(2xy)

y^{^{'}} = \frac{x ^{2} + 3 x}{2 x y}

(xy+2y+x+2)dy-(x^2-4)dx=0

(x y + 2 y + x + 2) d y - (x^{2} - 4) d x = 0

y^'=(3x^2+4x+2)/(2y+1)

y^{^{'}} = \frac{3 x ^{2} + 4 x + 2}{2 y + 1}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(2-y)/x ?
The solution for y^'=(2-y)/x is y=-(c_{1})/x+2