What is the integral of (3x^2)/(sqrt(1-x^3)) ?

The integral of (3x^2)/(sqrt(1-x^3)) is -2sqrt(1-x^3)+C

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integral of (3x^2)/(sqrt(1-x^3))

\int \frac{3 x ^{2}}{1 - x ^{3}} d x

- 2 1 - x^{3} + C

Solution steps

\int \frac{3 x ^{2}}{1 - x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x ^{2}}{1 - x ^{3}} d x

Apply u-substitution

: \int - \frac{1}{3 u} d u

= 3 \cdot \int - \frac{1}{3 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 (- \frac{1}{3} \cdot \int \frac{1}{u} d u)

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= 3 (- \frac{1}{3} \cdot 2 u^{\frac{1}{2}})

Substitute back

u = 1 - x^{3}

= 3 (- \frac{1}{3} \cdot 2 (1 - x^{3})^{\frac{1}{2}})

Simplify

3 (- \frac{1}{3} \cdot 2 (1 - x^{3})^{\frac{1}{2}}) : - 2 1 - x^{3}

= - 2 1 - x^{3}

Add a constant to the solution

= - 2 1 - x^{3} + C

\frac{d}{d x} (\frac{x ^{2} + x + 1}{x ^{3} - 3})

y^{2} d x + (2 x y + 1) d y = 0, y (9) = 90

x \to 0 + lim (tan^{x} (2 x))

\frac{d}{d x} (- a x - \frac{d}{x ^{2}})

\int e^{- x} \cdot ln (x) d x

What is the integral of (3x^2)/(sqrt(1-x^3)) ?
The integral of (3x^2)/(sqrt(1-x^3)) is -2sqrt(1-x^3)+C