What is the solution for x^'=x^{100}(t^2-1)(t^2-9),x(0)=1 ?

The solution for x^'=x^{100}(t^2-1)(t^2-9),x(0)=1 is x=-\sqrt[99]{5/(99t^5-1650t^3+4455t-5)}

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x^'=x^{100}(t^2-1)(t^2-9),x(0)=1

x^{^{'}} = x^{100} (t^{2} - 1) (t^{2} - 9), x (0) = 1

x = - 99 \frac{5}{99 t ^{5} - 1650 t ^{3} + 4455 t - 5}

Solution steps

x^{'} (t) = x^{100} (t^{2} - 1) (t^{2} - 9)

Solve separable ODE:

x = - 99 \frac{5}{99 t ^{5} - 1650 t ^{3} + 4455 t - 5}

x = - 99 \frac{5}{99 t ^{5} - 1650 t ^{3} + 4455 t - 5}

y^{^{'}} = 2 x y^{2}, y (2) = 1

\frac{d y}{d x} x y = x^{2} - x

\frac{d y}{d x} = \frac{5 x y}{( ln ( y ) ) ^{6}}

2 q^{^{'}} + 6 q = 2

\frac{d y}{d t} = 3 - \frac{3}{10} y

What is the solution for x^'=x^{100}(t^2-1)(t^2-9),x(0)=1 ?
The solution for x^'=x^{100}(t^2-1)(t^2-9),x(0)=1 is x=-\sqrt[99]{5/(99t^5-1650t^3+4455t-5)}