What is the solution for (dy)/(dx)=y^4cos(x) ?

The solution for (dy)/(dx)=y^4cos(x) is y=-\sqrt[3]{1/(3(sin(x)+c_{1))}}

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(dy)/(dx)=y^4cos(x)

\frac{d y}{d x} = y^{4} cos (x)

y = - 3 \frac{1}{3 ( sin ( x ) + c _{1} )}

Solution steps

\frac{d y}{d x} = y^{4} cos (x)

Solve separable ODE:

y = - 3 \frac{1}{3 ( sin ( x ) + c _{1} )}

y = - 3 \frac{1}{3 ( sin ( x ) + c _{1} )}

\frac{d r}{d t} = 4 r t

\frac{d y}{d x} = \frac{- 0.7}{cos ( y )}, y (0) = \frac{π}{4}

y^{^{'}} = (\frac{3 y}{x ln ( x )})

\frac{d y}{d t} - 0.04 y = 20000

y^{^{'}} = \frac{y}{9 t ^{2} + 1}

What is the solution for (dy)/(dx)=y^4cos(x) ?
The solution for (dy)/(dx)=y^4cos(x) is y=-\sqrt[3]{1/(3(sin(x)+c_{1))}}