What is (\partial)/(\partial x)(x^2y-y^2) ?

The answer to (\partial)/(\partial x)(x^2y-y^2) is 2xy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2y-y^2)

\frac{\partial}{\partial x} (x^{2} y - y^{2})

2 x y

Solution steps

\frac{\partial}{\partial x} (x^{2} y - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} y) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 y x - 0

Simplify

= 2 x y

\int \frac{sec ( x )}{sec ( x ) + tan ( x )} d x

x \to 2 + lim (\frac{3}{x - 2})

\frac{\partial}{\partial z} (3 z e^{x yz})

\frac{d ^{3}}{d x ^{3}} (sin (3 x))

\int - 4 x ln (x) d x

What is (\partial)/(\partial x)(x^2y-y^2) ?
The answer to (\partial)/(\partial x)(x^2y-y^2) is 2xy